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Handling, Preparation and Storage of StandardsICP Operations Guide: Part 3This section contains basic information on the handling, preparation and storage of standards, as well as basic calculations and nomenclature. HandlingObserving the following recommendations will save considerable time, money, and frustration:
CalculationsThe concentration units for chemical standard solutions used for ICP applications are typically expressed in µg/mL (micrograms per milliliter) or ng/mL (nanograms per milliliter). For example, a 1000 µg/mL solution of Ca+2 contains 1000 micrograms of Ca+2 per each mL of solution and a 1 µg/mL solution of Ca+2 contains 1000 ng of Ca+2 per milliliter of solution. To convert between metric concentration units the following conversions apply: Table 3.1: Mass portion of concentration unit where g = gram
Table 3.2: Volume portion of concentration unit where L = liter
The difference between ppm and µg/mL is often confused. A common mistake is to refer to the concentration units in ppm as a short cut (parts per million) when we really mean µg/mL. One ppm is in reality equal to 1 µg/g. In similar fashion ppb (parts per billion) is often equated with ng/mL. One ppb is in reality equal to 1 ng/g. To convert between ppm or ppb to µg/mL or ng/mL the density of the solution must be known. The equation for conversion between wt./wt. and wt./vol. units is: (µg/g) (density in g/mL) = µg/mL
and/or (ng/g) (density in g/mL) = ng/mL Therefore, if we have a solution that is 1000 µg/mL Ca+2 and know or measure the density to be 1.033 g/mL then the ppm Ca+2 = (1000 µg/mL) / (1.033 g/mL) = 968 µg/g = 968 ppm. When making dilutions the following equation is useful: (mLA)(CA) = (mLB)(CB)
For example, to determine how much of a 1000 µg/mL solution of Ca+2 required to prepare 250 mL of a 0.3 µg/mL solution of Ca+2 we would use the above equation as follows: (mLA)(1000 µg/mL) = (250 mL)(0.3 µg/mL)
(mLA) = [(250 mL)(0.3 µg/mL)]/ (1000 µg/mL) (mLA) = 0.075 mL = 75 µL PreparationWeight ≠ VolumeStandard chemical solutions can be prepared to weight or volume. The elimination of glass volumetric flasks may be necessary to eliminate certain contamination issues with the use of borosilicate glass or to avoid chemical attack of the glass. It is often assumed that 100 grams of an aqueous solution is close enough to 100 mL to not make a significant difference since the density of water at room temperature is very close to 1.00 (0.998203 at 20.0 °C). Diluting / preparing standard solutions by weight is much easier. Still, the above assumption should not be made. The problem is that trace metals standards are most commonly prepared in water + acid mixtures where the density of the common mineral acids is significantly greaten than 1.00. For example, a 5% v/v aqueous solution of nitric acid will have a density of ~1.017 g/mL which translates into a fixed error of ~1.7%. Higher nitric acid levels will result in larger fixed errors. This same type of problem is true for solutions of other acids to a degree that is a function of the density and concentration of the acid in the standard solution as described by the following equation (to be used for estimation only): dS = [(100-%) + (dA)(%)] / 100 Where: dS = density of final solution For example, lets estimate the density of a 10% v/v aqueous solution of nitric acid made using 70% concentrated nitric acid with a density of 1.42 g/mL. DS = [(100-%) + (dA)(%)]/100 = [(100-10) + (1.42)(10)]/100 = (90 + 14.2)/100 = 1.042 g/mL Acid ContentAnother area of confusion is the expression of the acid content of the solution. We all agree that it is important to matrix match the standard and sample solutions to avoid a fixed error in the solution uptake rate and/or nebulization efficiency sometimes referred to as a matrix interference. If a solution is labeled as 5% HNO3 what does this mean? If we take 5 mL of 70% concentrated nitric acid and dilute to a volume of 100 mL then this is 5% HNO3 (v/v) where the use of 70% concentrated acid is assumed. However, nitric acid can be purchased as 40%, 65%, 70%, and > 90%. Therefore, note the concentration of the concentrated acid used if different from the 'norm' as well as the method of preparation i.e. v/v or wt/wt or wt/v or v/wt. The wt. % concentrations of the common mineral acids, densities, and other information are shown in the following table: ![]() Acid Content in MolarityIt is important to know what the concentration units of the concentrated acid being used mean. Taking 70% concentrated nitric acid as an example means that 100 grams of this acid contains 70 grams of HNO3. The concentration is expressed at 70% wt./wt. or 70 wt. % HNO3. Some analysts prefer to work in matrix acid concentrations units of Molarity (moles/liter). To calculate the Molarity of 70 wt. % nitric acid we calculate how many moles of HNO3 are present in 1 liter of acid. Lets say that we tare a 1 liter volumetric flask and then dilute to the mark with 70.4 wt. % HNO3. We would then measure the weight of the solution to be 1420 grams. Knowing that the solution is 70.4 wt % would then allow us to calculate the number of grams of HNO3 which would be (0.704)(1420g) = 999.7 grams HNO3 per liter. Dividing the grams HNO3 by the molecular weight of HNO3 (63.01 g/mole) gives the moles HNO3 / L or Molarity which is 15.9 M. The above logic explains the following equation used for calculating the Molarity of acids where the concentration of the acid is given in wt %: [(% x d) / MW] x 10 = Molarity Where: % = wt. % of the acid Using the above equation to calculate the Molarity of the 70 wt % nitric acid we have: [(70.4 x 1.42) / 63.01] x 10 = 15.9 M Dilutions of the concentrated acid to prepare specific volumes of specified Molarity can be make using the (mLA)(CA) = (mLB)(CB) equation. Avoiding PrecipitatesIn the preparation of mixtures of the elements, it is good to avoid the formation of precipitates. It is common to form precipitates when concentrates of elements that are considered compatible (see part 1 of this series) are mixed. Many precipitates are not reversible (i.e., will not go into solution upon dilution). It is therefore best to add all of the acid and most of the water to the volumetric flask or standard solution container (dilutions to weight) before adding the individual element concentrate aliquots. Mixing after each aliquot addition is strongly advised. When diluting to volume it is often found that the solution is above room temperature. Therefore allow the solution to cool to room temperature and adjust to the mark with DI water. It is best to prepare the dilution the day before needed to allow for proper volume adjustment. StorageThe following are some considerations you may want to make before the storage of chemical standard solutions:
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